You slide a slab of dielectric between the plates of a parallel-plate capacitor. As you do this, the potential difference between the plates remains constant. What effect does adding the dielectric have on the energy stored in the capacitor?

The energy stored by the capacitor is increased when a dielectric is added, with voltage or potential difference staying the same.

Explanation:

The capacitance of a parallel-plate capacitor will increase as a dielectric is added between the plates. This is according to the following equation for capacitance:

Here, C is the capacitance, E is the dielectric constant, A is the area, and d is the distance between the plates.

Since the value of E is 1 or higher, the capacitance will increase once the dielectric is added.

The energy of a capacitor is found from the following equation:

Energy =

here C is the capacitance, and V is the voltage.

Since the voltage stays constant, while the capacitance increases in the energy equation, the overall energy stored by the capacitor also increases.

when heated, the valance electrons increased their speed and transferred the heat from electron to electron.   i just took the test.