Calculate the effective radiation dosage in sieverts for a 57 57 ‑kg person who is exposed to 4.2 × 10 9 4.2×109 particles of alpha radiation. Only 81 % 81% of the radiation is absorbed. Assume each alpha particle has an energy of 6.1 × 10 − 13 6.1×10−13 J and that the RBE of the alpha particles is 15 15 . Note that RBE is sometimes called the quality factor ( Q Q ).

  Dose = 5.4 10⁻⁴  Sv

Explanation:

The radiation dose absorbed by the body is 81% of the incident radiation, which is the number of particles per energy of each particle

    E = 0.81 n₀ E₀

    E = 0.81 4.2 10⁹ 0.81 6.1 10⁻¹³

    E = 2.075 10⁻³ J

Effective radiation dose

     Dose1 = n x RBE

     Dose1 = 2,075 10⁻³ 15

     Dose1 = 3.1 10⁻² REM

The effective radiation dose in sievert

          Dose = dose1 / m

          Dose = 3.1 10⁻² / 57

          Dose = 5.4 10⁻⁴      [j / kg]

          Dose = 5.4 10⁻⁴  Sv

a charge 3q is at the origin, and a charge −2q is on the positive x axis at x=a. part a where on the x-axis would you place a third charge so it would experience no net electric force? enter an expression for the exact answer, which will involve a square-root sign. (do not enter an approximate decimal answer.)

probably not the "magnets"in the magnet, so to speak, are thought to be electrons orbiting in shells. vurrent loops two sides to the loop