A small particle starts from rest from the origin of an xy-coordinate system and travels in the xy-plane. Its acceleration in the x-direction is 2m/s^2, and its acceleration in the y-direction is 1m/s^2. What is the x-coordinate of the particle when the y-coordinate is 12m?

When the y-coordinate is 12m, the x-coordinate of the particle is 24 m

Explanation:

Given;

y - component of acceleration = 1 m/s²

X - component of acceleration = 2 m/s²

distance traveled in y - direction, Dy = 12 m

To determine the distance traveled in X- direction, we obtain the duration of the displacement in y- direction.

Applying equation of motion;

Dy = ¹/₂ x at²

For distance traveled in x -direction;

Dx = ¹/₂ x at²

Dx = ¹/₂ x 2 x (4.9)² = 24.01 m ≅ 24m

Therefore, when the y-coordinate is 12m, the x-coordinate of the particle is 24 m

find the sum of the two horizontal vectors and the sum of the two vertical vectors

isoceles right angled triangle