What is the force of gravity between two 1000 kg cars separated by a distance of 20 m on a highway? 3. Using the force, calculated in # 2 above, and the weight of the car, calculate: Force (from #2) divided by the weight of car

Explanation:

Force of attraction between two masses M and m at distance d

= G mM / d² where G is universal gravitational constant .

Force of attraction between two cars of masses 1000kg each

= 6.67 x 10⁻¹¹ x 1000 x1000 / 20²

= 1.6675 x 10⁻⁷ N

Weight of car

mg

1000 x 9.8

= 9.8 x 10³ N

Ratio = force / weight of car

= 1.6675 x 10⁻⁷  / 9.8 x 10³

= .17 x 10⁻¹⁰

17 x 10⁻¹²

1.195000

explanation:

total mass=0.0117+0.0137+0.0881+0.0111

total mass= 0.01172kg

total velocity = 0.283-0.743+0.871-0.799+0.155+0.637+0.301=0.102

momentum=mv=0.1172*0.102=1.195000//

electrical potential energy =0.072 j

explanation:

electrical potential energy is given by

u= q δv

q= charge=6 c

δv= potential difference and is given by

δv= e d

e= electric field

d= distance=5 mm=0.005 m

δv=2.4 (0.005)=0.012 v

now electric potential energy= u= q δv

u=6 (0.012)

u=0.072 j