Physics, 02.03.2020 16:53 kaileyy06

A spring of force constant 300.0 N/m and unstretched length 0.240 m is stretched by two forces, pulling in opposite directions at opposite ends of the spring, that increase to 15.0 N. How long will the spring now be, and how much work was required to stretch it that distance

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Answer from: genyjoannerubiera

$F = K \Delta L$

And if we solve for the change of length we got:

$\Delta L = \frac{F}{K} =\frac{15N}{300 N/m}= 0.05 m$

And then the final length would be

$L_f = L_i + \Delta L = 0.24 +0.05 - 0.29 m$

So then we can find the work required to strech the spring with the following formula:

$W = \frac{1}{2} K (\Delta L)^2 =\frac{1}{2} (300 N/m) (0.05 m)^2 = 0.375 J$

Explanation:

We can't use the definition of work given by:

$W = F \Delta L$

Becuase the force in the last formula needs to be constant, and for this case the force associated to the spring is not constant during the movement.

For this case we have the following data given:

K = 300 N/m the constant of the spring

L = 0.24 m the length for the unstreched length

F = 15N represent the force acting

Since we have a change in the length we can write the Hooke's law like this:

$F = K \Delta L$

And if we solve for the change of length we got:

$\Delta L = \frac{F}{K} =\frac{15N}{300 N/m}= 0.05 m$

And then the final length would be

$L_f = L_i + \Delta L = 0.24 +0.05 - 0.29 m$

So then we can find the work required to strech the spring with the following formula:

$W = \frac{1}{2} K (\Delta L)^2 =\frac{1}{2} (300 N/m) (0.05 m)^2 = 0.375 J$

Answer from: Quest

scattering of light by tiny particles in air to produce the colors we see on sky, is dependent on the following factors:

(i) wavelength of light

(ii) size of the scattering particle

(iii) distance traveled by light through the atmosphere.

according to rayleigh's law of scattering, the amount of scattering is inversely proportional to the fourth power of its wavelength. shorter the wavelength, greater is its scattering. hence violet/blue light is scattered more than red.

sun's light is a composite light ( visible light) with wavelengths in the range 400 nm (violet) to 700 nm (red). as sunlight passes through our atmosphere, the molecules of air scatter light according to their wavelengths. during sunrise and sunset, the sun's position is below the horizon. hence light from the sun travels a greater distance in the atmosphere when compared to its position a noon.

as sunlight enters the earth's atmosphere, blue light is scattered away and at the end of its journey in the sky, only red and orange wavelengths remain in the beam.

hence at sunrise and sunset, the sky appears reddish orange.

Answer from: Quest

That depends on what kind of environ meant it is in in space it has the same force that was applied when the velocity was gained

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A spring of force constant 300.0 N/m and unstretched length 0.240 m is stretched by two forces, pull...

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