1.0 liter of 20c water is mixed with 4 liters of 40c water. What will be the temperature of this mixture

36°C

Explanation:

Heat gained by the cold water = heat lost by the warm water

mCΔT = mCΔT

(1000 g) (4.184 J/g/K) (T − 20°C) = (4000 g) (4.184 J/g/K) (40°C − T)

1000 (T − 20°C) = 4000 (40°C − T)

T − 20°C = 4 (40°C − T)

T − 20°C = 160°C − 4T

5T = 180°C

T = 36°C

it would be c. predictability