A capacitor consists of two parallel plates, each with an area of 15.0 cm2 , separated by a distance of 0.200 cm . The material that fills the volume between the plates has a dielectric constant of 4.00. The plates of the capacitor are connected to a 200 V battery. Part AWhat is the capacitance of the capacitor?C = FPart BWhat is the charge on either plate?Q = CPart CHow much energy is stored in the charged capacitor?U = J

Part A.  

Part B.

Part C.

Explanation:

Part A

The capacitance of a parallel-plate capacitor is given by

A is the area of the plates, d is the separation distance and ∈ is the permittivity of the material between the plates.

∈ is given as

is the dielectric constant and is the permittivity of free space with a value of .

Hence,

Part B

The charge, Q, on a capacitor is given by Q = CV

where V is its voltage and C its capacitance.

Part C

The energy of a capacitor is given by