A 0.45 Caliber bullet (m = 0.162 kg) leaving the muzzle of a gun at 860
m/s. what is the momentum?
140 kg*m/s
140 kg
62 kg*m/s
387 kg*m/s

If the heat engine is a perfect carnot cycle engine, thenefficiency = (t2-t1)/t2   where t1=temperature of cold reservoir ( ° k) = 135            t2=temperature of hot reservoir ( ° k)   = 325thereforeefficiency = (t2-t1)/t2 = (325-135)/325 = 0.5846 = 58%  note: this is the theoretical maximum efficiency of a perfect heat engine.   real-life engines do not achieve this value.