If a single circular loop of wire carries a current of 61 A and produces a magnetic field at its center with a magnitude of 1.30 10-4 T, determine the radius of the loop.

Given Information:  

Current = I = 61 A

Magnetic field = B = 1.30x10⁻⁴

Required Information:  

Radius of wire = r = ?

r = 0.093 meters

Step-by-step explanation:  

Biot-Savart Law is given by

B = μ₀I/2πr

Where μ₀ is the permeability of free space and it is basically a measure of resistance in the formation of magnetic field.

I is the current flowing through the wire and B is the magnitude of the magnetic field produced.  

Re-arranging the above equation to find out the radius of the loop

r = μ₀I/2πB

r = 4πx10⁻⁷*61/2π*1.30x10⁻⁴

r = 0.093 m

Hence, the radius of the loop wire is 0.093 meters.

answer: the correct answer is 1.

explanation: there are various process in which a radioactive nuclei decays:

1) alpha decay: in this process, a heavier nuclei decays into lighter nuclei by releasing alpha particle. the mass number is reduced by 4 units.

2) electron capture: in this decay process, a parent nuclei absorbs an electron and gets converted into a neutron. simply, a proton and an electron combines together to form a neutron. mass number does not change in this process.

3) gamma ray emission: it is a decay process in which an unstable nuclei gives excess energy by a spontaneous electromagnetic process. this decay releases . this process does not change the mass number.

4) positron emission: it is a type of decay process, in which a proton gets converted to neutron and an electron neutrino. this is also known as -decay. in this the mass number remains same.

from the above information, we see that only alpha-decay is producing a change in the mass number of the nucleus.

answer: 31, 5556. 952 seconds