A 0.530-kg basketball hits a wall head-on with a forward speed of 18.0 m/s. It rebounds with a speed of 13.5 m/s. The contact time is 0.100 seconds. (a) determine the impulse with the wall, (b) determine the force of the wall on the ball.

Explanation:

Change in momentum = m ( v -u )

= .53 ( 18+13.5 )

= 16.7 kg m/s

Impulse = change in momentum  

= 16.7 kg m/s  

b ) force x time = 16.7  

force = 16.7 / .1

= 167 N  

force of the wall on the ball

= 167 N.

massxgravity x heght=weightxheight= pe

4900=490xh

h=10