A concert loudspeaker suspended high off the ground emits 28.0 W of sound power. A small microphone with a 0.700 cm2 area is 55.0 m from the speaker. What is the sound intensity at the position of the microphone?

Explanation:

It is known that wave intensity is the power to area ratio.

Mathematically,    I =

As it is given that power is 28.0 W and area is .

Therefore, sound intensity will be calculated as follows.

             I =

               =

                =

or,             =

Thus, we can conclude that sound intensity at the position of the microphone is .

if the person is shown to have +90n, then ans is -10n.

if the person is shown to have -90n, then ans is +10n.