A spherical conductor with a radius of 65.7 cm has an electric field of magnitude 7.20 × 105 V/m just outside its surface. What is the electric potential just outside the surface, assuming the potential is zero far away from the conductor?

4.73V

Explanation:

Parameters given:

Radius of sphere = 65.7 cm = 0.657 m

Electric field = 7.2 * 10^5 V/m

Electric potential, V, is given in terms of Electric field as:

V = E * r

Where r = distance between charge and point of consideration.

Since we are considering a point just outside the spherical conductor:

V = 7.2 * 10^5 * 0.657

V = 4.73V

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