What total charge qq must be distributed uniformly over a spherical shell of radius R=0.30mR=0.30m to produce an electric field with magnitude 700 N/CN/C at a point just outside the surface of the shell?

7 x 10⁻⁹C

Inside the spherical shell, the electric field is zero, but outside the surface of the shell, the electric field (E) is given by;

E =            ----------------------(i)

Where;

k = proportionality constant = 9 x 10⁹Nm²/C²

Q = total charge over the spherical shell

r = the radius of the shell

From the question;

E = 700N/C

r = 0.30m

Substitute these values into equation (i) to get the total charge, Q, as follows;

700 =

700 =

700 x 0.09 = 9 x 10⁹ x Q

63 = 9 x 10⁹ x Q

Solve for Q;

Q = 63 / (9 x 10⁹)

Q = 7 x 10⁻⁹C

Therefore, the total charge is 7 x 10⁻⁹C

are their multiple choices ?

explanation:

  the grams     of oxygen gas   that can be produced     is 20.6   grams of o₂

calculation

2liclo₃ →   2 licl + 3 o₂

step 1:   find the moles of liclo₃

moles = mass÷ molar mass

from periodic table the molar mass of liclo₃ =6.9 +35.5   +(16 x3) =90.4 g/mol

moles=38.7 g÷90.4 g/mol=0.4281   moles

step 2:   use the   mole ratio   to calculate the moles of o2

from equation above, liclo₃: o₂   is 2: 3  

therefore the moles of   o₂=0.4281 moles x3/2 =0.6422   moles

step 3: find mass   of o₂

mass= moles x molar mass

from periodic table the   molar mass of   o₂ = 16 x2= 32 g/mol

mass=0.6422   moles   x   32 g/mol = 20.6 grams of o₂