In each cycle, the change in internal energy of the refrigerant when it leaves the compresser is 1.20×105 J . What is the work W done by the motor of the compressor?

The work done by the motor of the compressor is 1.20 x 10^5 J.

Explanation:

As the change in the internal energy is given as 1.20 x 10^5 J, and as there is no amount of heat added in the system this is given as

So the work done by the motor of the compressor is 1.20 x 10^5 J.

r = ρ x length / area  

ρ = r x area / length  

ρ is in ohm-meters  

in basic units, it is m³kg/s³a²  

i think this is it.

ya te mando la respuesta