A +5.0-μC point charge is placed at the 0 cm mark of a meter stick and a -4.0-μC charge is placed at the 50 cm mark. What is the net electric field at the 30 cm mark? (k = 1/4πε0 = 8.99 × 109 N ∙ m2/C2)

The net electric field is

Explanation:

Given that,

Charge at 0 mark = +5.0 μC

Charge at 50 mark = -4.0 μC

We need to calculate the electric field at 30 cm mark

Using formula of electric field

Where, q = charge

r = distance

Put the value into the formula

We need to calculate the electric field at 50 cm mark

Using formula of electric field

Put the value into the formula

We need to calculate the net electric field

Using formula of net electric field

Put the value into the formula

Hence, The net electric field is

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