The cheetah can reach a top speed of 114 km/h (71 mi/h). While chasing its prey in a short sprint, a cheetah starts from rest and runs 45 m in a straight line, reaching a final speed of 72 km/h. (a) Determine the cheetah’s average acceleration during the short sprint, and (b) find its displacement at t 5 3.5 s.

a= 4.4ms-2

Displacement= 26.95 m

Explanation:

First, the speed in km/hr must be converted to m/s so that we can apply it in solving the question. The motion started from rest hence the initial velocity is 0m/s. The average displacement is also obtained from the equations of motion as shown in the image attached.

  distance on the y-axis and time on the x-axis.

explanation:

the instantaneous velocity = change in position/time taken

the slope of the graph should give instantaneous velocity.

  slope of a graph = change in value of y -axis / change in values of x -axis

  comparing both the equations

    change in value of y -axis = change in position

  change in values of x -axis = time taken

so position values should be on the y axis and time values should be on the x axis.

distance on the y-axis and time on the x-axis.

the rearrangement of particles in a physical change. hope this