A 65.0-kg runner has a speed of 5.20 m/s at one instant dur- ing a long-distance event. (a) What is the runner’s kinetic energy at this instant? (b) How much net work is required to double his speed?

a)KE=878.8 J

b)W=2636.4 J      

Explanation:

Given that

mass ,m = 65 kg

Initial speed ,u = 5.2 m/s

a)

We know that kinetic energy KE is given as follows

m=mass

u=velocity

Now by putting the values in the above equation we get

KE=878.8 J

b)

We know that

Work done by all forces = Change in the kinetic energy

The final velocity , v= 2 u = 2 x 5.2 m/s

v= 10.4 m/s

Now by putting the values in the above equation we get

W=2636.4 J

a)KE=878.8 J

b)W=2636.4 J

vapour or gas assuming atmospheriv pressure