A particle moves with acceleration a(t) m/s^2 along an s-axis and has velocity vo m/s at time t=0. find the displacement and the distance traveled by the particle during the time interval

The displacement and distance is 22 m and 20.09 m.

Explanation:

Suppose, a(t)=11

v₀=-1 ; 0<t<2.....these are meant to be less than or equal to symbols

Given that,

Acceleration = 11 m/s²

We need to calculate the displacement

Using equation of velocity

On integration

Put the value of v₀

The displacement is 22 m.

We need to calculate the distance

Using formula of distance

Hence, The displacement and distance is 22 m and 20.09 m.

the answer is b ) square root of 5