An electric heater carries a current of 17.5 A when operating at a voltage of 120 V. What is the resistance of the heater?

16Ω

According to Ohm's law, the voltage (V) passing across a device is related to the current (I) flowing through it as follows;

V = I x R          -------------------(i)

Where;

R = the resistance of the device

According to the question, the device is the heater and it has the following details;

V = operating voltage = 120V

I = current = 17.5A

Now, substitute these values into equation(i) as follows;

120 = 17.5 x R

Solve for R;

R =

R = 16Ω

Therefore, the resistance of the heater is 16Ω

graph slopes whilst gas cools, then it is flat whilst conensation to liquid happens, the coolong liquid then graphs as a slope when it solidifies graph is flat

latent heat