A car weighing 13,000 N starts from rest and accelerates to 95.0 km/h in 5.00 s. The friction force is 1,450 N. Find the applied force (in N) produced by the engine. (Enter the magnitude.)

= 8.46 × 10³N

Explanation:

W = 1.3 × 10⁴

v₁ = 0

v (friction) = 95km/h = 26.4 m/s

t = 5s

f = 1450N

mass of body = W / g

=1.3 × 10⁴ / 9.8

=1327 kg

v(friction) = v + at

substitute in eqn 1

26.4 = 5a

a = 5.28 m/s

Force Net = F₁ + F₂ + F₃ = ma

F (engine) = ma + F

= 1327 (5.28) + 1450

= 8.46 × 10³N

a solenoid is created by wrapping a l = 90 m long wire around a hollow tube of diameter d = 4.5 cm.   the wire diameter is d = 0.9 mm.   the solenoid wire is then connected to a power supply so that a current of i = 9 a flows through the wire.

randomized variablesl = 90 m

d = 4.5 cm

d = 0.9 mm

i = 9 a                                          

write an expression for the number of turns, n, in the solenoid. you do not need to take into account the diameter of the wire in this calculation.

calculate the number of turns, n, in the solenoid.

write an expression for the length of the solenoid (l2) in terms of the diameter of the hollow tube d.

calculate the length of the solenoid (l2)   in meters.

calculate the magnitude of the magnetic field at the center of the solenoid in teslas.

explanation: