If the potential due to a point charge is 5.75 ✕ 102 V at a distance of 15.6 m, what are the sign and magnitude of the charge? (Enter your answer in C.)

Explanation:

The given data is as follows.

           Potential (V) =

           Distance (r) = 15.6 m

Let us assume that q is the magnitude of charge. Formula to calculate charge will be as follows.

            V =

             q =

                = C

As the potential due to charge is positive. Therefore, q is positive.

Thus, we can conclude that the sign of charge is positive and magnitude of the charge is C.

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