An 8.0-g bullet with a speed of 800 m/s is shot into a wooden block and penetrates 20 cm before stopping. What is the average force of the wood on the bullet? Assume the block does not move

The answer to your question is F = 16 N

Explanation:

Data

mass = 8 g

vo = 800 m/s

distance = 20 cm

force = ?

vf = 0 m/s

Process

1.- Calculate the acceleration of the bullet

Formula

  a = (vf² - vo²)/2d

Substitution

  a = (0 - 800)/2(0.2)

  a = -800/0.4

  a = 2000 m/s²

2.- Convert 8g to kg

           1000 g   1 kg

                 8 g   x

             x = (8 x 1)/1000

             x = 0.008 kg

3.- Calculate the force

Formula

      F = ma

Substitution

      F = (0.008)(2000)

Simplification and result

      F = 16 N

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answer: 2×10^-2kg

explanation: density= mass per volume

vol=mass/density

converting to s.i units we have;

3÷1000kg = 0.003

1.5÷100m = 0.15

0.003/0.15 = 0.02kg