If a second resistor with R2 = 19.0 Ω is connected in series with R1, what is the total rate at which electrical energy is dissipated by the two resistors?

Total rate at which electrical energy is dissipated by the two resistors are V²/R  or I²R.

Explanation:

When the two resistors are combined in series then the total resistance gets added.

If and are in series then total resistance, R =

Total resistance becomes + 19 Ω

The total electrical power dissipated is equivalent to the power dissipated.

We know,

Power = V²/R  or

Power = I²R

where, V is the potential difference between the ends

            I is the current supplied.

Therefore, total speed at which electrical power is consumed by the two resistors are V²/R  or I²R.

pythagoras' theorem

square root (-5^2+9^2)

square root (25+81)

square root (106)

angle is tan^-1(9/5)

neg x, pos y

no

explanation:

no i dont know how to solve this you should probably try to google the answer