A mail carrier leaves the post office and drives 2.00 km to the north. He then drives in a direction 60.0° south of east for 7.00 km. After dropping off a package, he drives 9.50 km 35.0° north of east to Starbucks. What is his distance from the starting point? (Hint: draw a picture) (3 sig figs) *

12.97 km

Explanation:

In order to find the resultant displacement, we have to resolve each of the 3 displacements along the x and y direction.

Taking north as positive y direction and east as positive x-direction, we have:

- Displacement 1: 2.00 km to the north

So

- Displacement 2: 60.0° south of east for 7.00 km

So

- Displacement 3: 9.50 km 35.0° north of east

So

So the net displacement along the two directions is:

So, the  distance between the initial and final position is equal to the magnitude of the net displacement:

568.98

explanation:

its math