A rope is attached to a block. The rope pulls on the block with a force of 240 N, at an angle of 40 degrees to the horizontal (this force is equal to the tension in the rope). What is the x-component of the force on the block due to the rope?

X Component is 183.85N

Explanation:

The x component of the force on the block due to the rope;

X = F cos @ where if is the force, @ is the angle mad with the block.

X = F cos @

X = 240 cos 40

Cos 40= 0.7660, so

X = 240 × 0.7660

X component= 183.85N// rounded to two decimal places.