1. Use Coulomb’s Law (equation below) to calculate the approximate force felt by an electron at point A in the schematic below. For the sake of simplicity, assume that the charge reservoirs, Q- and Q+ , can be treated as point charges each 2.5 cm away from point A and 5.0 cm away from each other. Make sure to denote which direction the force will act. The red and blue regions indicated in the schematic are conductors. Here, Q- is equal to the charge of six electrons, and Q+ is equal to the charge of six protons.

Explanation:

From the data it appears that A is the middle point between two charges.

First of all we shall calculate the field at point A .

Field due to charge -Q ( 6e⁻ ) at A

= 9 x 10⁹ x 6 x 1.6 x 10⁻¹⁹ / (2.5)² x 10⁻⁴

= 13.82 x 10⁻⁶ N/C

Its direction will be towards Q⁻

Same field will be produced by Q⁺ charge . The direction will be away

from Q⁺  towards Q⁻ .

We shall add the field  to get the resultant field  .

= 2 x 13.82 x 10⁻⁶

= 27.64 x 10⁻⁶ N/C

Force on electron put at A

= charge x field

= 1.6 x 10⁻¹⁹ x 27.64 x 10⁻⁶

= 44.22 x 10⁻²⁵ N

pe = weightxheight = 2000x1000=2,000,000joules