The truss system below is supported by a pin at A and a roller at C. When unloaded, truss member AC has length L = 2022 mm. The truss members are made of steel pipes with cross-sectional area Ac = 3265 mm? and elasticity modulus E = 216 GPa. A vertical and a horizontal load of magnitude P= 521 kN are applied at joint B. The angle is 0 =44º

the answer would be c

f=ma a/f/m a= 480/60 a = 8m/s/s that is quick wow

the rearrangement of particles in a physical change. hope this

initial speed when it is dropped is 150 ft/s

now at the same moment the acceleration due to gravity is perpendicular to its velocity

so as we know that

now we have centripetal acceleration a = 32 ft/s^2 as its perpendicular to velocity

while tangential acceleration at the same moment will be zero

so

now radius of curvature is given as

so the radius of curvature just after it is dropped is 703.125 ft