2. If the area of the large piston is 1,000 times the area of the small piston. How
does the force on the large piston compare to the force on the small piston?

The force will be magnified by 1000 times.

Explanation:

The pressure in both the pistons are same.

= Force exerted on first piston

= Force exerted on second piston

= Area of first piston

= Area of second piston

Now,

                                          =

As,   = 1000

                                          =

                                         = 1000

Force on large piston will be 1000 times the force on small piston.

low freq = 100 mhz

low wavelength =101.7m

length = 3x10^8/freq