Physics, 22.02.2020 00:41 liyah7771

On May 27, 1931 Auguste Piccard and Paul Kipfer reached an altitude of 15.8 km (51,775 ft) in a balloon. The air density at that altitude is very low so they needed to travel in a pressured gondola. The air at that altitude is also very cold. How were they able to stay warm?

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they had to recoup to the thermal insulation of two things the gondola in the travel and in clothes for extreme cold for them

Explanation:

On this trip the researchers used a hydrogen balloon. In general, the temperature drops by about 2ºC / 300 m, so the temperature at that height is of the order of -50 to -60ºC.

It is not possible to keep the temperature with flames, since oxygen is very scarce and the fire would not occur, in addition to the danger of fire with hydrogen.

Due to the lack of oxygen at this altitude, pressurized oxygen tanks must be carried out so that the exit at atmospheric pressure is heated.

Therefore they had to recoup to the thermal insulation of two things the gondola in the travel and in clothes for extreme cold for them

Answer from: Quest

Look it up you feel me

Answer from: Quest

russian is not my first language, so i'm afraid i can't write out an answer in russian, but hopefully you can find a way to do so. here's my best translation of the problem: you're given a plot of a particle's position in one-dimensional space over time, and you're asked to find either the total distance traveled by the particle after 6 seconds had elapsed, or the total displacement of the particle after 6 seconds.

if you want the total distance traveled, you would first need to determine the particle's velocity as a function of time, then integrate that over the 6-second interval. we know the position function is quadratic with roots at 0 and 6, so we have

$x(t)=ax(x-6)$

where $a$ is unknown. because the position is parabolic, there is symmetry about the midpoint at $t=3$ , and we know that

$x(3)=10\implies -9a=10\implies a=-\dfrac{10}9$

so that the position function is

$x(t)=-\dfrac{10}9x(x-6)$

which means the velocity is

$v(t)=\dfrac{\mathrm dx}{\mathrm dt}=-\dfrac{20}9x+\dfrac{60}9$

then the total distance traveled is

$\displaystyle\int_{t=0}^{t=6}|v(t)|\,\mathrm dt=\left\{\int_{t-0}^{t=3}-\int_{t=3}^{t=6}\right\}v(t)\,\mathrm dt=20$

so the total distance traveled is 20 m.

on the other hand, if you want to find displacement: the particle starts at $x=0$ and ends at $x=0$ , so its displacement is 0.

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On May 27, 1931 Auguste Piccard and Paul Kipfer reached an altitude of 15.8 km (51,775 ft) in a ball...