A capacitor is charged until its stored energy is 7.54 J. A second capacitor is then connected to it in parallel. If the charge distributes equally, what is the total energy stored in the electric fields

2 J

Explanation:

A charged capacitor of capacitance with energy of 7.54 J, is connected in parallel with another capacitor , so the charge is equally distributed between them.

(a) The energy stored in the capacitor before it being connected to the other capacitor is:

The energy stored in the electric field is the sum of the energies of the two capacitors:

since the charge equally distributed,   = = . and since they are connected in parallel the potential difference on both of them is the same :

hence,

hi there!

out of the two, (b) precision would be more reasonable.   however, both a and b could be pretty reasonable.

-awesomerepublic   : )