An electron (charge −e=−1.60×10−19C−e=−1.60×10−19C) is at rest at a distance 1.00×10−10 m 1.00×10−10m from the center of a nucleus of lead (charge +82e=+1.31×10−17C+82e=+1.31×10−17C) . You may treat both objects as point charges. How much work would you have to do to move the electron to a distance 5.00×10−10m5.00×10−10m from the center of the lead nucleus

Explanation:

According to Coulomb's law, the force of attraction between two point charges, and , separated by a distance is given by

is a constant with a value of .

When we substitute the values from the question,

This value is negative because it is in a direction towards the positive charge.

The work done in moving the electron from the nucleus is

This is negative because work is done on the electron, not by it.

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c) power lifting, will be your answer.

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deku ❤