A 26.0 kg kg crate is initially moving with a velocity that has magnitude 3.75 m/s m/s in a direction 37.0 ∘ ∘ west of north. 1. How much work must be done on the crate to change its velocity to 5.31 m/s m/s in a direction 63.0 ∘ ∘ south of east? 2. Express your answer to three significant figures and include the appropriate unit.

184 J

Explanation:

We are given that

Mass of crate=26 kg

Initial velocity=u=3.75 m/s

Direction= W of N

Final velocity=v=5.31 m/s

Direction=S of E

We have to find the work done on the crate to change its velocity.

By using work energy theorem

Work done=Change in kinetic energy

Work done=

Work done=

Work done=367 J-183 J=184 J

d₁ = displacement of tern from arctic to antarctic = 11000 miles

d₂ = displacement of tern from antarctic to arctic =   - 11000 miles

d = total displacement for the journey

total displacement for the journey is given as

d = d₁ + d₂

d = 11000 + (-11000)

d = 0 miles

t₁ = time of travel from arctic to antarctic = 3 months = 3 x 30 days = 90 days

t₂ = time of travel from antarctic to arctic = 3 months = 3 x 30 days = 90 days

t = total time of travel

total time of travel is given as

t = t₁ + t₂

t = 90 + 90

t = 180 days

average velocity is given as

average velocity = total displacement/ total time

v = d/t

v = 0/180

v = 0 miles/day

answer and explanation;