A 0.500-kg stone is moving in a vertical circular path attached to a string that is 75.0 cm long. The stone is moving around the path at a constant frequency of 1.50 rev/sec. At the moment the stone is overhead, the stone is released. The velocity of the stone when it leaves the circular path is

A. 5.55 m/s.
B. 7.07 m/s.
C. 7.75 m/s.
D. 8.35 m/s.
E. 9.00 m/s.

B. 7.07 m/s

Explanation:

The velocity of the stone when it leaves the circular path is its tangential velocity, , which is given by

where is the angular speed and is the radius of the circular path.

is given by

where is the frequency of revolution.

Thus

Using values from the question,

Note the conversion of 75 cm to 0.75 m

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