A pendulum with a period of 1 s on Earth, where the acceleration due to gravity is g, is taken to another planet, where its period is 2 s. The acceleration due to gravity on the other planet is most nearly .

The acceleration due to gravity on the other planet is 1/4 of the acceleration due to gravity on earth

Explanation:

Using the formula;

      ......................equation 1

for earth we have;

        ..................equation 2

for the other planet we have;

      ...................equation 3

divide the equation 3 by equation 2;

The gravitational acceleration on the other planet will be one-fourth of the Earth's gravitational acceleration.

The formula for the period of the pendulum,

Where,

- period

- length

- gravitational acceleration

On the earth,

......................1

On the other planet,

.....................2

From equations 1 and 2,

Therefore, the gravitational acceleration on the other planet will be one-fourth of the Earth's gravitational acceleration.

To know more about gravitational acceleration.

pythagoras' theorem

square root (-5^2+9^2)

square root (25+81)

square root (106)

angle is tan^-1(9/5)

neg x, pos y