Physics, 20.02.2020 19:16 any80

Two large parallel metal plates are 1.2 cm apart and have charges of equal magnitude but opposite signs on their facing surfaces. Take the potential of the negative plate to be zero. If the potential halfway between the plates is then 6.6 V, what is the electric field in the region between the plates?

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Answer from: moraleserica011

E=1100V/m

Explanation:

Given required solution

V=6.6v E=? V=Ed ; V is the potential difference between

d=D/2=1.2cm/2=0.6cm=0.006m the halfway

E is the electric field between the two

plates.

d is the distance between the halfway.

So we can use the above formula to calculate the electric field.

V=Ed from this E=V/d substitute the values from the given equation.

E=6.6v/0.006m

E= 1100 v/m

Answer from: Quest

28. evolution

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Answer from: Quest

Answer: it will take 4.36 seconds to reach her average velocity 10.69 miles/hour.explanation: we have equation of motion $s=ut+\frac{1}{2} at^2$ ,where s is the displacement, a is the acceleration, u is the initial velocity and t is the time taken.average velocity = displacement/ time taken.average velocity = 10.69 miles/hr = 10.69*1.6*1000/(60*60) = 4.75 m/s4.75 = s/ts = 4. 1we also have acceleration = 2.18 m/s², initial velocity = 0 m/s $s=0*t+\frac{1}{2} *2.18*t^2$ $s=1.09t^2[/ 2equating equation 1 and 2 [tex]4.75t = 1.09t^2\\ \\ t=4.36 seconds.$ so it will take 4.36 seconds to reach her average velocity 10.69 miles/hour.

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