Container A holds 717 mL 717 mL of ideal gas at 2.50 bar 2.50 bar . Container B holds 179 mL 179 mL of ideal gas at 4.30 bar 4.30 bar . If the gases are allowed to mix together, what is the partial pressure of each gas in the total volume?

Explanation:

For this case we can use the Boyle law given by:

Gas A

The final volume for this case would be the addition of the two volumes given

We can calculate the final pressure of the gas A:

We need to remember that 1 bar = 1.01325 atm, we convert the initial pressure for the gas A and we got:

And finally we got:

Gas B

The final volume for this case would be the addition of the two volumes given

We can calculate the final pressure of the gas A:

We need to remember that 1 bar = 1.01325 atm, we convert the initial pressure for the gas A and we got:

And finally we got:

And the total pressure for this case at the end would be:

2b2t

explanation:

2b2t

get the total number of pieces of fruit and divide it by 4 to get the average. the result is the answer to the problem. 14 total number of fruits and there are 4 members. 14 divided by 4 is equals to 3.5.