The middle-C hammer of a piano hits two strings, producing beats of 1.50 Hz. One of the strings is tuned to 260.00 Hz. What frequencies could the other string have?

f₂ = 261.5Hz  or 258.5Hz

Explanation:

The beat frequency = /f₁ - f₂/

where f₁ and f₂ are the frequencies of individua waves

f(beat) = 1.5Hz

f₁( frequency of one string) = 260Hz

f(beat) = /f₁ - f₂/

1.5Hz = /260Hz - f₂/

to solve this equation

we make it into two seprate equation and solve it separately

260Hz - f₂ = 1.5Hz

f₂ = 260Hz - 1.5Hz

  = 258.5Hz

260Hz - f₂ = -1.5Hz

f₂ = 260Hz + 1.5Hz

   = 261.5Hz

therefore, the two possible frequencies of the other strings are

f₂ = 258.5Hz or  261.5Hz

maria has a savings account that is earning simple interest. if she started with $200 in the account and has earned a total of $8 in interest in two years, what is the rate of the account? use the formula  .