The ammonia molecule NH3 has a permanent electric dipole moment equal to 1.47 D, where 1 D = 1 debye unit = 3.34 × 10-30 C-m. Calculate the electric potential in volts due to an ammonia molecule at a point 53.1 nm away along the axis of the dipole. (Set V = 0 at infinity.)

And we can express the last expression like this:

Explanation:

For this case we know the dipole moment given by 1.47 D. We know also that

And we need to calculate the electric potential due to an ammonia molecule at a point 53.1 nm away along the axis of the dipole

We can convert the dipole moment like this:

And the potentital at the desired point can be calculated with the following formula:

Where is a constant, , and since we are assuming V=0 we can conclude that

If we replace the info given we got:

And we can express the last expression like this:

And this would be our final answer for this case.