Car A is traveling at a constant speed vA = 130 km / h at a location where the speed limit is 100 km / h. The police offi cer in car P observes this speed via radar. At the moment when A passes P, the police car begins to accelerate at the constant rate of 6 m/s2 until a speed of 160 km / h is achieved, and that speed is then maintained. Determine the distance required for the police offi cer to overtake car A. Neglect any nonrectilinear motion of P.

Distance = 713.303m

Explanation:

To determine the distance required for the police officer to overtake car A, we simply calculate the time t for which the police car and the speeding car have traveled equal distances from point P

the motion is shown below

=130 km/h==> 36.1 m/s

=0, a=6 m/s^2 (till =160 km/h)

so time taken to reach =160 km/h==> 44.4 m/s t=7.4 sec

in this time the car A travelled distance () is given by =*t=267.2 m

clearly > so police will have to move

now

S=(-)=102.9m

V=-=8.3 m/s

==12.4 s

=t+

       =19.8 s

come closer and become far apart and become steam/gas

wavelength divides in half and speed stays the same.