If you put two 60 W bulbs in series across a 120 V outlet, how much power would each consume if its resistance were constant?

Each would use 15 W power.

Together they would use 30 W.

Explanation:

For the 60 W bulb R = ΔV²/P= (120)²/60=14400/60= 240 OHMS

We can use Ohms Law to find the current

I =ΔV/R= 120/240= 0.5 Amperes

When they are placed in series the total resistance is about 480 ohms, so each bulb sees a current of 120/480 = 0.25 A.

Using the power equation to find the power of the bulbs in series

P= I²R= 0.25²* 240= 0.0625 *240= 15 W

Each would use 15 W power.

Together they would use 30 W.

c.the charges if the proton and electron and gravity

see the picture for the vector

the magnitude of the vector by pythagorean theorem

r = √( (-10)^2 + (3)^2 ) = √109

magnitude = √109 units

the direction angle between vector and x-axis is

tan^(-1)(3/10) = 16.699

so the direction is approximately 16.7 degrees north of west