An unknown charge sits on a conducting solid sphere of radius 9.0 cm. If the electric field 14 cm from the center of the sphere has magnitude 2.7 103 N/C and is directed radially inward, what is the net charge on the sphere?

The net charge on the sphere is - 5.9 × 10⁻⁹ C = - 5.9 nC

Explanation:

The electric field (E) produced by a charge of magnitude Q, at a point with distance r away from the charge, is given by

E = kQ/r²

where k = Coulomb's constant = 9.0 x 10⁹ Nm²/C²

The electric field 14 cm (0.14 m) from the sphere is 2.7 × 10³ N/C

2.7 × 10³ = 9.0 x 10⁹ × Q/(0.14²)

Q = (2.7 × 10³ × 0.14²)/(9.0 x 10⁹) = 5.9 × 10⁻⁹ C

Since the charge is directed inwards towards the centre of the sphere, the sign on it will be -ve. Q = - 5.9 × 10⁻⁹ C

b) The electric field 9 cm (0.09 m) from the sphere will be

E = kQ/(0.09²) = (9 × 10⁹ × 5.9 × 10⁻⁹)/(0.09²) = 6555.56 = 6.56 × 10³ N/C

c. 7/3

step-by-step explanation:

a rational number is like pi- it is a repeating decimal.

a. is -1.8

b. 2.236068

c. 2.3333333333333333333

d.   is 3

i hope that ! =)

the answer is the first electromagnet (a). this is because it has more coils around the ferromagnetic material. increasing the number of coils increases the surface area in which the metal interacts with the current in the coil. this enables more atoms in the metal to become aligned hence becoming more magnetized.