According to a simplified model of a mammalian heart, at each pulse approximately 20 g of blood is accelerated from 0.25 m/s to 0.35 m/s during a period of 0.10 s. What is the magnitude of the force exerted by the heat muscle?

0.02 N

Explanation:

Force: This can be defined as the product of mass and acceleration. The S.I unit of force is Newton.

The formula of force is given as,

F = ma Equation 1

Where F = force exerted by the heart muscle, m = mass of the blood, a = acceleration.

Also,

a = (v-u)/t Equation 2

Where v = final velocity, u = initial velocity, t = time.

Given: v = 0.35 m/s, u = 0.25 m/s, t = 0.1 s

Substitute into equation 2

a = (0.35-0.25)/0.1

a = 0.1/0.1

a = 1 m/s².

Also given: m = 20 g = 0.02 kg.

Substitute into equation 1

F = 0.02(1)

F = 0.02 N.

Hence the force = 0.02 N

0.02 N.

Explanation:

Given:

m = 20 g

= 0.02 kg.

vi = 0.35 m/s

vo = 0.25 m/s

t = 0.1 s

Force, F = m * a

Where,

m = mass of the blood

a = acceleration.

Acceleration, a = (vi - vo)/t

Where,

vi = final velocity

vo = initial velocity

t = time.

a = (0.35 - 0.25)/0.1

= 0.1/0.1

= 1 m/s².

F = 0.02 * 1

= 0.02 N.

answer; ///(74) degrees is your answer..

a solenoid is created by wrapping a l = 90 m long wire around a hollow tube of diameter d = 4.5 cm.   the wire diameter is d = 0.9 mm.   the solenoid wire is then connected to a power supply so that a current of i = 9 a flows through the wire.

randomized variablesl = 90 m

d = 4.5 cm

d = 0.9 mm

i = 9 a                                          

write an expression for the number of turns, n, in the solenoid. you do not need to take into account the diameter of the wire in this calculation.

calculate the number of turns, n, in the solenoid.

write an expression for the length of the solenoid (l2) in terms of the diameter of the hollow tube d.

calculate the length of the solenoid (l2)   in meters.

calculate the magnitude of the magnetic field at the center of the solenoid in teslas.

explanation: