An ideal transformer with N1 5 1000 and N2 5 250 is connected with an impedance Z22 across winding 2. If V1 5 1000 /08 V and I1 5 5 /2308 A, determine V2, I2, Z2, and the impedance Z9 2, which is the value of Z2 referred to the primary side of the transformer.

W= fd
where f is an applied force and d is the distance over which it is applied. when a parachuting skydiver is at constant velocity, he is experiencing "terminal velocity", the point at which his acceleration down is canceled out by air resistance. that means that the resisting force of the air is equal to his weight, but in the opposite direction. with this, we can solve for the work done by the force.
w = fd
w = (92.0)(9.81 m/s^2) (325)
w= 2.93 x 10^5 j
the value for work in this case is positive because it is pushing up on the skydiver, who has a downward force of gravity.
therefore the answer is 2.93 x 10^5 j

Ithink it’s: light bounce if off a mirror