A water droplet of mass ‘m’ and net charge ‘-q’ remains stationary in the air due to Earth’s Electric field.
(a) What must be the direction of the Earth’s electric field?
(b) Find an expression for the Earth’s electric field in terms of the mass and charge of the droplet.

(a) the electric field of the Earth will be directed towards the negatively charged water droplet.

(b) E = (9.8*m)/q

Explanation:

Part (a) the direction of the Earth’s electric field

Electric field is always directed towards negatively charged objects.

The water droplet has a negative charge ‘-q’, therefore the electric field of the Earth will be directed towards the negatively charged water droplet.

Part (b) an expression for the Earth’s electric field in terms of the mass and charge of the droplet

The magnitude of Electric field is given as;

E = F/q

where;

f is force and q is charge

Also from Newton's law, F = mg

where;

m is mass and g is acceleration due to gravity = 9.8 m/s²

E =  F/q = mg/q

E = (9.8*m)/q, Electric field in terms of mass and charge of the droplet.

most voltage drop calculators want the distance between the source and destination. then internally, they double it so both the source and return wires are calculated. but you need to know which distance the calculator uses so you're not half of what you should be or double what you should be.

most circuit breakers will not take a #6 directly, so the electrician will have to splice on a smaller pigtail. you also have to upsize the grounding wire when you upsized the ungrounded (hot) wire (see note in 250.122). this will preclude using most cable assemblies, as a cable with #6 copper will most likely only have a #10 grounding conductor. you need a #6 grounding conductor if the circuit is 20a. a #8 cable is no better, as it will have a #10 grounding conductor too. but most 20a breakers will take a #8 directly.

in your related post, you didn't say what type of load this is. if it is a light or heater, voltage drop won't be a big issue. if this is a motor, the current needs are huge at startup and the voltage drop can pose a problem. if this is a motor, knowing if the motor is under much load during startup will answer the voltage drop effect (a saw is easier to start than a compressor).

i just did an experiment like this in my science class. also the answer is yes, it will get separated because they are two opposites meaning if they are opposite they can not attract.

hope this .!