Certain sharks can detect an electric field as weak as 1.00 V/m. To grasp how weak this field is, if you wanted to produce it between two parallel metal plates by connecting an ordinary 1.50 V AA battery across these plates, how far apart would the plates have to be?

1.5 m

Explanation:

Electric Field: This can be defined as the force per unit charge which is exerted at a point in an electric field. The S.I unit of Electric Field is N/C or V/m.

The formula connecting electric field, Electric potential and distance is given as,

V = E×r Equation 1

Where V = Electric potential or potential difference of the battery, E = Electric Field, r = distance between the plates.

make r the subject of the equation

r = V/E Equation 2

Given: V = 1.50 V, E = 1.0 V/m.

Substitute into equation 2

r = 1.5/1.0

r = 1.5 m.

Hence the distance between the plates = 1.5 m

The distance between the plates = 1.5 m.

Explanation:

Electric Field can be defined as the force per unit charge. The S.I unit of Electric Field is N/C or V/m.

Mathematically,

V = E * d

Where,

V = potential difference

= 1.5 V

E = Electric Field exerted

= 1.0 V/m

d = distance between the plates.

d = 1.5/1.0

= 1.5 m.

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dec 23, 2016 - a load of bricks weighing 680 n a distance of 10 m across a parking lot. if if the worker pushes the cart with a constant force of 209 n, what work= force x distance = 220 n x 10 m = 2200 n.m = 2200 j i don't know where the person got it from, but the initial part, work= force x distance me.