It is known that the gravitational force of attraction between two protons is much weaker than the electrical repulsion. For two protons at a distance d apart, calculate the ratio of the size of the gravitational attraction to that of the electrical repulsion. Specifically, find the magnitude of Fgravitational/Felectrical. Use the following data: k = 8.99×109 Nm2/C2 charge on one of the protons = 1.60×10-19 C G = 6.67×10-11 Nm2/kg2 mass of one of the protons = 1.67×10-27 kg.

Explanation:

We are given that

Charge on proton=

Mass of one proton=

The distance between two protons=d

Gravitational attraction force=

Using the formula

Gravitational attraction force between two protons=..(1)

Electric force =

Electric repulsive force between two protons=

(75°f − 32) × 5/9 = 23.889°c

work: w = fd (given)

work done by chet   =50*1 = 50 j

work done by mika =40*2 = 80 j

work done by sara =30*1.5 = 45 j

work done by bill =60*0.5 = 30 j

students in order from the greatest amount of work done to the least is mika> chet> sara> bill

hence option (b) is correct.