One mole of nickel (6 1023 atoms) has a mass of 59 grams, and its density is 8.9 grams per cubic centimeter. You have a long thin bar of nickel, 2.7 m long, with a square cross section, 0.06 cm on a side. You hang the rod vertically and attach a 27 kg mass to the bottom, and you observe that thebar becomes 1.38 cm longer. From thesemeasurements, it is possible to determine the stiffness of one inter-atomic bond in nickel.1) What is the spring stiffness of the entire wire, considered as asingle macroscopic (large scale), very stiff spring? 2) How many side-by-side atomic chains (long springs) are there in this wire? This is the same as the number ofatoms on the bottom surface of the nickel wire. Note that the cross-sectional area ofone nickel atom is (2.23 10-10)2 m2.3) How many interatomic bonds are there in one atomic chain running the length of the wire?4) What is the stiffness of a single interatomic "spring"?

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Answer: a charge of -1.0  × 10⁻⁴ c must be placed  at x = 26 m.the sign of the charge will be the same sign as the  -4.0  µc charge.======electricstatic force between two point charges  is given by    where k is coulomb's constant,  8.99×10⁹  n·m²/c², q₁ and q₂ are the point charges, and r is the distance between the two point charges.assign positive to q₁let q₁ =  6.0 µc, q₂ = -4.0  µc, q₀ represent the charge at the origin, and q₃ represent this new charge to place.the charge at the origin q₀ would experience the following force f₀₁ from q₁, with r = 6.0 m (note that 1  µc = 10⁻⁶ c)    the force from q₂    the force from q₃    the net force on the origin charge, q₀, has to be zero for no electrostatic forcehaving an equation where k and q₀ can be divided out of the equation will allow us to solve for q₃    isolating:     a charge of -1.0  × 10⁻⁴ c must be placed  at x = 26 m.the sign of the charge will be the same as the  -4.0  µc charge