To identify situations when position, velocity, and /or acceleration change, realizing that change can be in direction or magnitude. If an object's position is described by a function of time, r⃗ (t) (measured from a nonaccelerating reference frame), then the object's velocity is described by the time derivative of the position, v⃗ (t)=dr⃗ (t)dt, and the object's acceleration is described by the time derivative of the velocity, a⃗ (t)=dv⃗ (t)dt=d2r⃗ (t)dt2. It is often convenient to discuss the average of the latter two quantities between times t1 and t2: v⃗ avg(t1,t2)=r⃗ (t2)−r⃗ (t1)t2−t1 and a⃗ avg(t1,t2)=v⃗ (t2)−v⃗ (t1)t2−t1.

Inelastic is the answer your looking for.

Distance covered = speed x timethe distance traveled going against the stream = distance traveled with the stream.therefore it is the speed and the time that are the variables.as he travels the same distance both ways, speed x time is the same for each way.going upstream his speed is 4 kph; going downstream his speed is 6 kph.therefore we have two simultaneous equations: time upstream x 4 = time downstream x 6time upstream + time downstream = 60 minutestherefore we have the equation: time upstream = 6/10 hour, time downstream therefore = 4/10 hour.distance traveled at 4km/hr in 6/10 hour = 24/10 = 2.4km.check: distance traveled at 6km/hr in 4/10 hour = 24/10 = 2.4km.

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