A car of mass 1000.0 kg is traveling along a level road at 100.0 km/h when its brakes are applied. Calculate the stopping distance if the coefficient of kinetic friction of the tires is 0.500. Neglect air resistance. (Hint: since the distance traveled is of interest rather than the time, xx is the desired independent variable and not tt. Use the Chain Rule to change the variable: \frac{dv}{dt}=\frac{dv}{dx}\frac{dx }{dt}=v\frac{dv}{dx} dt dv = dx dv dt dx =v dx dv .)

Explanation:

Given:

Now the kinetic frictional force:

where:

N= normal force of reaction by the ground on the car, which is equal to the weight of the car

Therefore the acceleration of the car due to frictional force:

Now the stopping distance:

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