How much heat energy, in kilojoules, is required to convert 46.0 gg of ice at −−18.0 ∘C∘C to water at 25.0 ∘C∘C ?

1. Energy for 18 to 0 * C

Q = M * Cs * T

(46)(2.09)(18) = 1.73 kj

2. Fusion Energy

Q = M * Change in Fusion      Enthalpy of Fusion Given = 334 J

(46)(334 j) = 15.36 KJ

3. Energy for 0 to 25 * C

(46)(4.18)(25) = 4.807 kj

4. Add all of it up

1.73 + 15.36 + 4.807 = 21.89 kj

Is the answer 21.89 KJ

most voltage drop calculators want the distance between the source and destination. then internally, they double it so both the source and return wires are calculated. but you need to know which distance the calculator uses so you're not half of what you should be or double what you should be.

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d) physical means can be used to separate the components of air.